假设现在有一个泛型类T的实例对象t,该T类的全部信息都未知。
要求:打印输出实例对象t的类名、属性个数、属性名、属性的数据类型、属性值。
1、我们根据输出的内容要求定义一个实体类如下:
public class GeneralDataModel { /// <summary> /// 类名 /// </summary> public string class_name { get; set; } /// <summary> /// 属性个数 /// </summary> public int prop_count { get; set; } /// <summary> /// 单个属性的信息 /// </summary> public List<PropInfoItem> props { get; set; } } public class PropInfoItem { /// <summary> /// 属性名 /// </summary> public string prop_name { get; set; } /// <summary> /// 属性数据类型 /// </summary> public string prop_data_type { get; set; } /// <summary> /// 属性值 /// </summary> public string prop_value { get; set; } }
2、编写一个方法,该方法的主要功能是解析实例对象t,并输出步骤1中格式的内容。方法代码实现如下:
public static GeneralDataModel DataAnalysis<T>(T t) { var data_type = t.GetType(); var propInfo = data_type.GetProperties(); var list = new List<PropInfoItem>(); foreach (var item in propInfo) { var e = new PropInfoItem { prop_name = item.Name, prop_data_type = item.PropertyType.Name, prop_value = item.GetValue(t) == null ? "" : item.GetValue(t).ToString() }; list.Add(e); } var res = new GeneralDataModel { class_name = data_type.Name, prop_count = propInfo.Count(), props = list }; return res; }
1、假设现在有一个学生类如下所示:
public class Student { /// <summary> /// 学号 /// </summary> public int no { get; set; } /// <summary> /// 姓名 /// </summary> public string name { get; set; } /// <summary> /// 年级 /// </summary> public string grade { get; set; } /// <summary> /// 出生年月 /// </summary> public DateTime birth { get; set; } }
2、根据该类实例化了一个st对象如下:
var st = new Student() { no = 123456, name = "张三", grade = "六年级", birth = DateTime.Now };
3、调用DataAnalysis方法解析st,并打印输出结果:
var res = DataAnalysis(st); Console.WriteLine(JsonConvert.SerializeObject(res));
4、输出结果如下:
{ "class_name": "Student", "prop_count": 4, "props": [ { "prop_name": "no", "prop_data_type": "Int32", "prop_value": "123456" }, { "prop_name": "name", "prop_data_type": "String", "prop_value": "张三" }, { "prop_name": "grade", "prop_data_type": "String", "prop_value": "六年级" }, { "prop_name": "birth", "prop_data_type": "DateTime", "prop_value": "2022/5/7 17:21:12" } ] }
5、看到输出结果后,感觉完美的解决了问题。
1、因为种种原因,学生类增加了两个属性,同时实例化对象的创建形式也变了,变化后的形式如下:
public class Student { public Student() { } public Student(string id_card_no, string address) { this.id_card_no = id_card_no; this.address = address; } /// <summary> /// 学号 /// </summary> public int no { get; set; } /// <summary> /// 姓名 /// </summary> public string name { get; set; } /// <summary> /// 年级 /// </summary> public string grade { get; set; } /// <summary> /// 出生年月 /// </summary> public DateTime birth { get; set; } /// <summary> /// 身份证(受保护类型) /// </summary> protected string id_card_no { get; set; } /// <summary> /// 家庭地址(私有类型) /// </summary> private string address { get; set; } }
var st = new Student("777888202005071111", "家庭地址私有,暂时不方便透露") { no = 123456, name = "张三", grade = "六年级", birth = DateTime.Now };
2、再次调用DataAnalysis方法解析st,并打印输出结果:
var res = DataAnalysis(st); Console.WriteLine(JsonConvert.SerializeObject(res));
3、输出结果如下:
{ "class_name": "Student", "prop_count": 4, "props": [ { "prop_name": "no", "prop_data_type": "Int32", "prop_value": "123456" }, { "prop_name": "name", "prop_data_type": "String", "prop_value": "张三" }, { "prop_name": "grade", "prop_data_type": "String", "prop_value": "六年级" }, { "prop_name": "birth", "prop_data_type": "DateTime", "prop_value": "2022/5/7 17:40:21" } ] }
4、看到输出结果时,咦?怎么似乎好像哪里不对?新增的两个属性怎么没有被解析并输出呢?
1、通过种种途径或者查阅其他资料你了解到了反射的相关知识,并找到了一个名为GetRuntimeProperties的方法。
2、修改原先的解析方法代码如下:
public static GeneralDataModel DataAnalysis<T>(T t) { var data_type = t.GetType(); var refPropInfo = data_type.GetRuntimeProperties(); var list = new List<PropInfoItem>(); foreach (var item in refPropInfo) { var e = new PropInfoItem { prop_name = item.Name, prop_data_type = item.PropertyType.Name, prop_value = item.GetValue(t) == null ? "" : item.GetValue(t).ToString() }; list.Add(e); } var res = new GeneralDataModel { class_name = data_type.Name, prop_count = refPropInfo.Count(), props = list }; return res; }
3、再一次调用DataAnalysis方法解析st,并打印输出结果:
var res = DataAnalysis(st); Console.WriteLine(JsonConvert.SerializeObject(res));
4、输出结果如下:
{ "class_name": "Student", "prop_count": 6, "props": [ { "prop_name": "no", "prop_data_type": "Int32", "prop_value": "123456" }, { "prop_name": "name", "prop_data_type": "String", "prop_value": "张三" }, { "prop_name": "grade", "prop_data_type": "String", "prop_value": "六年级" }, { "prop_name": "birth", "prop_data_type": "DateTime", "prop_value": "2022/5/7 17:52:12" }, { "prop_name": "id_card_no", "prop_data_type": "String", "prop_value": "777888202005071111" }, { "prop_name": "address", "prop_data_type": "String", "prop_value": "家庭地址暂时不方便透露" } ] }
5、看到这输出结果,脸上露出了满意的笑容,啊~~~问题终于解决了,开森^_^
1、方法前后变化仅仅只有一处,由GetProperties
变为了GetRuntimeProperties
。
2、溯源发现:
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